GOODBYE TO LABORIOUS METHOD
My project
is a simple way to find the difference between the cubes of two consecutive integers.
If we want to find the difference between
two cubes we should do a laborious method. For example,
23³-22³= (23×23×23)-(22×22×22)
Instead of
doing all these laborious method, to calculate the difference between the cubes
of two consecutive integers we can do a simple method.
That is,
For any
consecutive integers a&b
If a>b
then,
a³-b³=3ab+1
Examples:
· 3³-2³=27-8=19
3ab+1=3×6+1=19
· 205³-204³=8615125-8489664=125461
3ab+1=3×41820+1=125461
· -100³—101³=-1000000-1030301=30301
3ab+1=3×10100+1=30301
For any
consecutive integers a&b
If
b>a then,
a³-b³=-(3ab+1)
|
Examples:
· 2³-3³=8-27= -19
- (3ab+1)=-(3×6+1)= -19
· -101³—100³=-1030301+100000= -30301
- (3ab+1)=-(3×10100+1)= -30301
I have also findout a simple method
to check whether the sum of two cubes is right. That is,
a²+b²=2ab+ (a-b) ²
Examples:
· 4²+2²=16+4=20
2ab+(a-b)²=2×4×2+ (4-2)²=16+4=20
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